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Accepted Solution

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Answer:f(x) ⇒ Graph Cg(x) ⇒ Graph Dh(x) ⇒ Graph Aj(x) ⇒ Graph EStep-by-step explanation:* Lets revise the quadratic function and its inverse- The quadratic function if f(x) = x², its vertex is the origin- To find its inverse, switch x and y and solve for y∵ y = x² ⇒ switch x and y∴ x = y² ⇒ solve for y∴ y = ± √x - If y = √x , then the graph is up the x-axis- If y = -√x , the graph is down the x-axis∴ The inverse function is y = √x* Now lets solve the problem- All the figure are the inverses of the quadratic function y = x² ∵ f(x) = √(x - 1) # x - 1 means the graph move to the right 1 unit∴ Its vertex is (1 , 0)* The graph of f(x) = √(x - 1) is graph C∵ g(x) = -√x # The sign (-) means the graph reflected about the x-axis∴ Its vertex is (0 , 0) but the graph under the x-axis* The graph of g(x) = -√x is graph D∵ h(x) = √x ∴ Its vertex is (0 , 0)- It is the inverse of y = x² , the graph up to the x-axis* The graph of h(x) = √x is graph A∵ j(x) = -√(x - 1) # x - 1 means the graph move to the right 1 unit# The sign (-) means the graph reflected about the x-axis∴ Its vertex is (1 , 0) , the graph down the x-axis* The graph of j(x) = -√(x - 1) is graph E